((x^2-16)/(2x))*((18)/(3x-12))

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Solution for ((x^2-16)/(2x))*((18)/(3x-12)) equation: 


D( x )

2*x = 0

3*x-12 = 0

2*x = 0

2*x = 0

2*x = 0 // : 2

x = 0

3*x-12 = 0

3*x-12 = 0

3*x-12 = 0 // + 12

3*x = 12 // : 3

x = 12/3

x = 4

x in (-oo:0) U (0:4) U (4:+oo)

((x^2-16)/(2*x))*(18/(3*x-12)) = 0

(18*(x^2-16))/(2*x*(3*x-12)) = 0

( 18 )

18 = 0

x belongs to the empty set

( x^2-16 )

1*x^2 = 16 // : 1

x^2 = 16

x^2 = 16 // ^ 1/2

abs(x) = 4

x = 4 or x = -4

x in { 4} 

x = -4

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